Lcof25

Lcof 25.合并两个排序的链表

输入两个递增排序的链表,合并这两个链表并使新链表中的节点仍然是递增排序的。

示例1:

​ 输入:1->2->4, 1->3->4
​ 输出:1->1->2->3->4->4

迭代

class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode head = new ListNode(-1);
ListNode res = head;
while (l1 != null && l2 != null) {
if (l1.val < l2.val) {
res.next = l1;
l1 = l1.next;
} else {
res.next = l2;
l2 = l2.next;
}
res = res.next;
}
if (l1 == null) {
res.next = l2;
}
if (l2 == null) {
res.next = l1;
}
return head.next;
}
}

递归

class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
if (l1.val < l2.val) {
l1.next = mergeTwoLists(l1.next, l2);
return l1;
} else {
l2.next = mergeTwoLists(l1, l2.next);
return l2;
}
}
}
Author: Jiayi Yang
Link: https://jiayiy.github.io/2020/07/06/Lcof25/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.